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=Variational methods: Sound waves in solid and fluid materials=
=Variational methods: Sound waves in solid and fluid materials=


 
 
 


==Elasticity in solids==
Consider a solid body or a fluid at rest. Under the action of an external force it will start to move or flow and the work done the force is transformed in kinetic energy. This is the case of a rigid body or an incompressible fluids, but in real materials part of the work can be used to induce a deformation.
A compression for example has an ergetic cost both for fluids and solids, while a change in shape (shear) has a cost only for solids.


If the  deformation is not too large the work is stored in terms of elastic energy and it is  reversibly released when the force is removed. As a consequence, after a sudden pertubation, elastic waves propagates in the material.
Similarly to light, which are waves associated to the electromagnetic field, the sound that we can ear are waves associated to the elastic field. But which field?


Under the action of external forces a solid body moves. But it can also be deformed, i.e. it can change volume and shape. The first succesful attempt to describe this phenomenon is provided by the ''theory of elasticity''. The theory is based on two assumptions:
At variance with their electromagnetic cousins, elastic waves can propagate only inside materials and display a quite different nature in solids with respect to fluids. Here we derive their equations of motion in both kind of material and  compute their speed.


1) the solid body can modeled as a continuum medium


2) the energetic cost of the deformation is kept at the lowest order in perturbation.


The fundamental equations of elasticity have been established by Cauchy and Poisson in the twenties of the 19th century, well before the discovery of the atomic structure of matter.
Here we consider a perfectly isotropic continuum medium and show how sounds propagate in it.


==Part I: Elasticity in solids==
 
 
 


The first succesful attempt to describe deformations in solids is provided by the ''theory of elasticity''. The theory is based on the assumptions that (1) the solid body can modeled as a continuum medium and (2) the energetic cost of the deformation is kept at the lowest order in perturbation. The fundamental equations of elasticity have been established by Cauchy and Poisson in the twenties of the 19th century, well before the discovery of the atomic structure of matter.


===The strain tensor===
 
 
 


Each point of the body can be identified with its postion in the space:
==Displacement fields and strain tensor==


 
 
 
Here we review the basic objects of elastic theory that you have done last year (e.g. see pages 62-66 of '' Mécanique du solide et des matérieaux, partie 1, Pascal Kurowski'').
Consider a perfectly isotropic continuum medium with density mass  <math>\rho_0</math> at equilibrium:. Assume that at time <math> t=0  </math> a body is at rest and no external forces are applied. Each point of the body can be identified with its postion in the space:


<center><math> \vec r = (x_1=x, x_2 =y, x_3 =z) </math></center>
<center><math> \vec r = (x_1=x, x_2 =y, x_3 =z) </math></center>


When the body is deformed a point located in <math> \vec r  </math> moves to a new location <math> \vec r_{\text{new}}  </math>. The displacement, <math> \vec u= \vec r_{\text{new}}-\vec r </math>, differs from point to point of the body and is then a function of the original position <math> \vec r  </math>.
Then under the action of external forces the body starts to be deformed: the point located in <math> \vec r  </math> moves to a new location <math> \vec r_{\text{new}} </math> at time <math> t>0 </math> . The displacement, <math> \vec u= \vec r_{\text{new}}-\vec r </math>, differs from point to point of the body and is then a ''field'', namely
The ''displacement''vectorial field
a function of the original position <math> \vec r  </math>:


<center><math> \vec u( \vec r) =  \left(u_1( \vec r), u_2( \vec r), u_3( \vec r)\right)  </math> </center>
<center><math> \vec u( \vec r,t) =  \left(u_1( \vec r,t), u_2( \vec r,t), u_3( \vec r,t)\right)  </math> </center>


encodes then all informations about the deformation of the body. However large displacements does not always correspond to large deformation as the body can move rigidly without deformation. To quantify how much a body is deformed we consider two points at an infinitesimal distance <math> d \ell </math>.  
the ''displacement field'' encodes then all information about the deformation.  


* Assuming small deformations, show that the distance <math> d \ell_{\text{new}} </math> after the deformation can be written as:
However large displacements does not always correspond to large deformation as the body can move rigidly without deformation. To quantify how much a body is deformed it is useful to introduce the symmetric ''strain tensor'' <math> \epsilon_{ik}</math> :
<center><math>  \epsilon_{ik} = \frac12 \left( \partial_k u_i + \partial_i u_k \right)\, , \quad \text{with}\;  \partial_k =\frac{\partial}{\partial x_k} \quad(1) </math></center>




'''Q1:''' Take two points at a distance <math> d \ell </math> and compute the distance <math> d \ell_{\text{new}} </math> after a small deformation. Show that  at the lowest order in the deformation it can be written as 
<center><math> d \ell_{\text{new}}^2 \approx d \ell^2 + 2 \sum_{i,k} \epsilon_{ik} d x_i dx_k  </math></center>
<center><math> d \ell_{\text{new}}^2 \approx d \ell^2 + 2 \sum_{i,k} \epsilon_{ik} d x_i dx_k  </math></center>


The tensor <math> \epsilon_{ik}</math> is called ''strain tensor'', is symmetric and defined as


<center><math> \epsilon_{ik} = \frac12 \left( \frac{\partial u_i}{\partial x_k} + \frac{\partial u_k}{\partial x_i} \right) \quad (1) </math></center>
=== Compression: the (relative) density field===
 
 
&nbsp;
&nbsp;
&nbsp;
 
Consider now a local compression at the point <math>\vec r</math>. The volume element around the point, <math> d V= dx_1 \, dx_2 \, dx_3 </math>, is squeezed to a smaller volume <math>d V_{\text{new}}</math> and the density mass will locally increases from the uniform value <math>\rho_0</math>:
<center><math>  \rho(\vec r,t)=\rho_0+\delta \rho(\vec r,t)=\rho_0 \left( 1+\sigma(\vec r,t)\right)</math> </center>
The ''scalar field'' <math>  \sigma(\vec r,t)</math> represents the relative fluctuation of the density.
 


* Consider now a volume element <math> d V= dx_1 \, dx_2 \, dx_3 </math> and show that at the first order in perturbation one has


<center><math> d V_{\text{new}}\approx d V \left(1+  \sum_{i} \epsilon_{ii}\right) \quad  </math></center>
<center><math>\sigma(\vec r,t) = \frac{\rho(\vec r,t)-\rho_0}{\rho_0} =- \frac{d V_{\text{new}}-d V}{ d V} </math> </center>


This means that the trace of the strain tensor identifies with the relative change in volume  <math> (d V_{\text{new}}-d V)/ d V </math> of the body. In general all deformation can be represented as the sum of a uniform compression (change in volume without change of shape) and a shear (change of shape without change of volume):
'''Q2:''' Show that at the first order in perturbation one has
 
<center><math> d V_{\text{new}}\approx d V \left(1+  \text{Tr}(\epsilon)\right) \quad  </math></center>.
 
Tip: it is convenient to write the element volume in the principal coordinate around the point <math>\vec r</math>. There the symmetric deformation tensor is diagonal.
 
Conclude that
<center><math>\sigma(\vec r,t) =-\text{div}(\vec u) </math> </center>
 
 
&nbsp;
&nbsp;
&nbsp;
 
 
In general all deformation can be represented as the sum of a uniform compression (change in volume without change of shape) and a shear (change of shape without change of volume):


<center><math>  \epsilon_{ik}= \left(\epsilon_{ik} -\frac{1}{3} \delta_{ik}\text{Tr}(\epsilon)\right) + \frac{1}{3} \delta_{ik} \text{Tr}(\epsilon) \quad \text{with} \quad \delta_{ik}= \begin{cases}
<center><math>  \epsilon_{ik}= \left(\epsilon_{ik} -\frac{1}{3} \delta_{ik}\text{Tr}(\epsilon)\right) + \frac{1}{3} \delta_{ik} \text{Tr}(\epsilon) \quad \text{with} \quad \delta_{ik}= \begin{cases}
Line 50: Line 94:
\end{cases} \quad
\end{cases} \quad
(2)  </math></center>
(2)  </math></center>
The first term is a shear as its trace is zero. The second term is a compression.
The first term is a shear as its trace is zero. The second term is a compression/rarefaction.


===Elastic waves===
== Energy cost of the deformation==


To describe the oscillations induced by sudden deformations one as to consider time dependent displacement vectors:


<center><math> \vec u( \vec r,t) =  \left(u_1( \vec r,t), u_2( \vec r,t), u_3( \vec r,t)\right)  </math> </center>
&nbsp;
&nbsp;


If one neglects the gravity the total energy of the body is given by the elastic potential energy and the kinetic term that we evaluate in the following.


====Elastic energy of a deformation: the Hooke law à la Landau====
A body at rest, in abscence of external force and at thermal equilibrium  does not display any deformation, this means that when the strain tensor is zero for all points, the potential energy displays a minimum. As a consequence for small deformations the first terms of the expansion of the potential energy must be quadratic in the strain tensor (elastic approximation). 
The more general quadratic form can be written as <math> \int d \vec r \sum_{ijkl} \epsilon_{ij} \, C_{ijkl}  \, \epsilon_{kl}  </math>, where the tensor <math>C_{ijkl}</math> contains all the elastic moduli. For an isotropic material the energy cost should be frame independent and  we can write a simpler quadratic form that we will discuss in class:


To evaluate the elastic energy associated with a small deformation we note that in abscence of external force and at thermal equilibrium the body does not display any deformation. This observation as two consequences:
<center><math>E_{\text{el}} =\int d \vec r  \left[ \frac{K}{2} \text{Tr}(\epsilon)^2 + \mu \sum_{ik} \left( \epsilon_{ik}-\frac{1}{3}\delta_{ik} \text{Tr}(\epsilon) \right)^2\right] </math></center>
The first term  accounts for the cost of the change in volume, the second for the change of shape. The positive constants <math> K , \mu  </math> are respectively the bulk and the shear modulus and have dimensions of a pressure. These two constants are material dependent and fully describe its elastic properties.


1) When the strain tensor is zero for all points, the energy displays a minimum.


2) The first terms of the energy expansion must be quadratic in the strain tensor. Linear terms are incompatible with the condition of a minimum 


The more general quadratic form can be written as <math> \int d \vec r \sum_{ijkl} \epsilon_{ij} \, C_{ijkl}  \, \epsilon_{kl}  </math>, where the tensor <math>C_{ijkl}</math> contains all the elastic moduli. For an isotropic material, consideration of the principle of material frame indifference leads to the conclusion that the strain energy density function can be written in a simpler form (we will discuss it in class):
&nbsp;
&nbsp;


<center><math>E_{\text{el}} =\int d \vec r \left[ \frac{K}{2} \sum_i \epsilon_{ii}^2 + \mu \sum_{ik} \left( \epsilon_{ik}-\frac{1}{3}\delta_{ik} \text{Tr}(\epsilon) \right)^2\right] </math></center>
==Kinetic energy==


The first term  accounts for the cost of the change in volume, the second for the change of shape. The positive constants <math> K , \mu  </math> are respectively the bulk and the shear modulus and have dimensions of a pressure. These two constants are material dependent and fully describe its elastic properties.


====Kinetic Energy====
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&nbsp;


The mass contained in an infinitesimal volume around the point located in <math> \vec r </math> is <math> \rho \, d V= \rho \, d \vec r </math>, with <math> \rho</math> the mass density of the body. The total kinetic energy can then be written as
The kinetic energy can then be written as
<center>
<center>
<math> T = \rho \int d \vec r  \left( \dot u_1^2 ( \vec r,t)  +\dot u_2^2 ( \vec r,t)+\dot u_3^2 ( \vec r,t) \right) </math></center>
<math> T = \frac{\rho_0}{2} \int d \vec r  \left( \dot u_1^2 ( \vec r,t)  +\dot u_2^2 ( \vec r,t)+\dot u_3^2 ( \vec r,t) \right) </math></center>
where <math> \rho_0</math> is the mass density of the material at rest. Here used the fact that the mass contained in an infinitesimal volume around the point located in <math> \vec r </math> is <math> \rho_0 \, d V= \rho_0 \, d \vec r </math>.
 
 
&nbsp;
&nbsp;
 
== Equation of motion with the variational principle==
 
 
 
&nbsp;
&nbsp;
 
'''Q3:''' Show that the potential elastic energy can be re-written in the following form:
 
<center><math> E_{\text{el}} = \int d \vec r  \left[\frac{1}{2}\left( K-\frac{2}{3} \mu\right) \left( \sum_l \partial_l u_l \right)^2 +\frac{\mu}{4} \sum_{l,m} (\partial_l u_m +\partial_m u_l)^2 \right]  </math> </center>
 
 
&nbsp;
 
 
The associated action is given by
<center><math> S= \int d t \int d \vec{r} \, \mathcal{L} =  \int d t \int d \vec{r} \, \left(  \mathcal{T}_{\text{kin}} - \mathcal{E}_{\text{el}} \right)  </math></center>
where <math>  {\mathcal L} </math> is the Lagrangian density,  <math>\mathcal{T} </math> is the kinetic energy density, and <math> \mathcal{E}_{\text{el}} </math> is the potential energy density
 
 
&nbsp;
 
'''Q4:''' Write explicitly <math> \mathcal{T}, \mathcal{E}_{\text{el}} </math>.


==== The action for a simplified model====
'''Q5:''' Using the variational methods show that the equation of motion for a given component  <math> u_i(\vec{r},t)</math>  of the displacement writes
<center><math> \rho_0 \ddot u_i = \sum_k
\frac{d}{d x_k} \frac{d}{d  (\partial_k u_i)} \mathcal{E}_{\text{el}} </math></center>
'''Q6:''' Show that the 3 equations of motion  take the form


To simplify the calculation we will neglect the dependence on <math> z,y </math> of the displacement vector which becomes: 
<center><math> \rho_0 \ddot u_i = \mu \sum_k
<center><math> \vec u(x,t) = \left(u_1(x,t), u_2(x,t), u_3(x,t)\right)  </math> </center>
\frac{\partial^2 u_i}{\partial x_k^2}  + ( K+\frac{\mu}{3}) \sum_k \frac{\partial^2 u_k}{\partial x_i \partial x_k} </math></center>
* Within this approximation write the elastic energy in term of <math> \partial_x u_x, \partial_x u_y, \partial_x u_z</math>
and organize them  in the vectorial form:
The action associated to this energy is
<center><math> \int_{t_1}^{t_2} d t \int_0^1 d x \, \mathcal{L} (x,t) </math></center>
where <math>  {\mathcal L}(x,t) </math> is the Lagrangian denisty
* Write explicitly <math>  {\mathcal L}(x,t) </math>.
* Using the variational methods write the 3 equations of motion for <math> u_x(x,t),  u_y (x,t), u_z(x,t)</math>.
* Compute the longitudinal mode velocity and the transverse mode velocity.


<center><math> \ddot {\vec u} = c_t^2 \nabla^2 {\vec u} + (c_l^2-c_t^2) \vec{\text{grad}} \;\text{div}\,(\vec u)</math></center>
'''Q7:''' Provide the expression of the two constants  <math> c_t, c_l</math>
To make progress we will consider plane waves, namely deformations that are fonction of <math>(x, t)</math> only.
<center><math> {\vec u}({\vec r}, t)={\vec u}(x,t)</math></center> 
This means that all <math>y, z</math> derivatives
are zero.


==Sound waves in fluids==
'''Q8:''' Write the explicit form of the three wave equations. They are D'Alembert equations, explain why <math> c_t, c_l</math> are called transverse mode velocity and  longitudinal mode velocity.


Consider a uniform ideal gas of equilibrium mass density <math>\rho_0 </math> and equilibrium pressure <math>P_0</math>. Let us investigate the longitudinal oscillations of such a gas. Of course, these oscillations are usually referred to as sound waves.


&nbsp;


It is possible to show that the result obtained for plain waves is very general: in solids elastic waves has two transverse components propagating at velocity <math> c_t</math> and one longitudinal component propagating at velocity <math> c_l > c_t </math>.


Conclude that the elastic field in fluids is the displacement vectorial field.




<gallery  widths=500px heights=300px  mode="packed">
Image:earthquake.png|Seismic waves recorded by a seismograph after an earthquake. Longitudinal waves are the quickest and for this reason called primary (P-waves), then arrive the transverse waves, for this reason called secondary (S-waves). Finally it's the turn of Rayleigh waves which are also  solution of the D'Alembert equation but propagate only on the Earth surface. They are slower and less damped then bulk waves.
Image:earthquake2.png| The time delay between the P and S waves grows with  seismograph-epincenter distance. The measure of three independent seismographs allows thus to identify the location of the epicenter.
</gallery>


==Elasticity in fluids==


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&nbsp;


A fluid does not oppose a change in its shape with any internal resistance, but displays a finite energy cost to compression. Using the same reasoning used before we can write the Lagrangian density:


<center><math>  \mathcal{L} (\vec{r},t) = \frac{\rho_0}{2}  \dot{\vec{u}}^2  - \frac{K}{2} (\text{div}(\vec{u}))^2    </math></center>
'''Q9''' Show that the associated  equation of motion
<center><math>  \rho_0\,    \ddot \vec{u} = K  \vec{\text{grad}}\left(\text{div}(\vec{u})\right)    </math></center>


'''Q10''' Show that the previous equation of motion corresponds to the D'Alembert Equation for the scalar field <math>  \sigma(\vec r,t)  </math>.
Conclude that the elastic field in fluids is the scalar relative density field.


[[File:earthstructure]]    [[File:image008.jpg]]


===Gravity===
We write now the gravitational potential as a functional of <math>y(x)</math>. We will use two different methods. We suppose that the total mass of the line in <math>M</math>.


* Suppose that springs are massless and  <math>N</math> identical masses are located at positions <math>y_1,y_2,\ldots</math>


* Combine your finding for elasticity and gravity and show that the shape of the elastic line is parabolic


=== Dynamics ===
<gallery  widths=500px heights=400px  mode="packed">
Image:Voyage.png|Men landed on the Moon 50 years ago, but a Journey to the Center of the Earth remains science fiction. The deepest artificial holes go only 12 km into the Earth's crust.
Image:Earthsturcture.png|The chemical-physical structure of the 6000 km of our planet are known by the ''trip reports'' of seismic waves. For example we know the core is fluid as secondary waves cannot travel deeper than 3000 Km.
</gallery>


We want to study the motion of the elastic line in absence of gravity and in presence of small oscillations. The shape of the line is now time dependent <math> y(x,t)</math>.
==Sound speed in perfect gas==
   
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&nbsp;


*Write the kinetic energy associated to the <math> N </math> masses located at <math>y_1(t),y_2(t),\ldots, y_N(t) </math>. Take the continuum limit.
Generally speaking the sound speed (the transverse one for solids) takes the form


The action associated to the elastic chain is
<center><math>c_l =\sqrt{\frac{K + (4 \mu)/3}{\rho_0}}</math> </center>
<center><math> \int_{t_1}^{t_2} d t \int_0^1 d x \, \mathcal{L} (x,t) </math></center>
where <math>  {\mathcal L}(x,t) </math> is the Lagrangian denisty
* Write explicitly <math>  {\mathcal L}(x,t) </math> .
* Write the equation of motion of the chain  using the minimum action principle. This equation is the D'Almbert equation.


the constant K is much bigger in solid then liquids and much bigger in liquids then gases. For this reason sound propagates much faster in solids (6 km /s in steal) then in water (1 km /s) or, even worst, in air (331 m /s at T=273 K).


For perfect gases it is possible to evaluate the bulk modulus and then the speed sound velocity in gases. Newton did the first attempt, but he made a mistake corrected later by Laplace. Consider the gas at equilibrium at temperature <math>T</math>, pressure <math>P_0</math> and density <math>\rho_0</math>.  We consider a sudden expansion/compression from a volume  <math>V_0</math> around  <math>\vec r</math> to <math>V_0+\delta V</math> and evaluate again the stored elastic energy. It can be written as the work associated to the  expansion/compression:
<center><math> E_{\text{el}} =  \frac{K}{2}\int d \vec r  \text{Tr}(\epsilon)^2 =  \frac{K}{2} \frac{(\delta V)^2}{V_0} =- \int_{V_0}^{V_0+\delta V} \,  P(V) \, d V  </math> </center>
the pressure can be expanded around the equlibrium
<center> <math>    P(V) \approx P_0 + \left(\frac{\partial P }{\partial V}\right)_{V=V_0}  (V-V_0)  </math></center>




'''Q11:''' Show that
<center><math>  K= - V_0 \left(\frac{\partial P }{\partial V}\right)_{V=V_0} </math> </center>


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===Kinetic Energy===
Newton idea was that the the compressed  gas remain at the same temperature <math>T</math>, so that
<center><math>P  V= </math> constant</center>


In a first time we can start from the discrete description of a system of N atoms at  positions <math> {\vec u}_1(t), {\vec u}_2(t) ,\ldots ,  {\vec u}_N(t) </math>.
'''Q12:''' Show that in this case
* Write the kinetic energy, <math>  T </math>, for this system as a function of mass of the atom <math>m </math>.
<center><math>  K=  P_0 </math> </center>
* Consider the limit of small oscillations. Take the continuum limit: <math> {\vec u}_i(t) \to \vec u(\vec r,t) </math> and show that the kinetic energy writes
and using that at 1 atmosphere (<math>101325</math> Pa) the density of air is <math>1.293</math> kg/m<math>^3</math> (at T=273 K)) compute the sound speed predicted by Newton.
<center><math> T= \frac{\rho_0}{2} \int \, d \vec{r}  \,  \dot{\vec{u}}^2 (\vec r,t)  </math> </center>
===Potential Energy===
In order to write the full Lagrangian we need to find the potential energy associated to the oscillations. During the oscillations the mass density can have small fluctuations
<center><math> \rho(\vec r,t)=\rho_0+\delta \rho(\vec r,t)=\rho_0\left( 1+\sigma(\vec r,t)\right)</math> </center>
The scalar field <math> \sigma(\vec r,t)</math> represents the relative fluctuation of the density.


As a consequence of these fluctuations, the volume  which contains a given mass <math>M </math> expands from the initial value <math>V_0 </math> to a new value  <math>V_0 +\delta V</math>. The pressure inside the domain also  fluctuates <math>P=P_0+\ldots </math>. The variation of potential energy is given by the work associated to the volume expansion:
&nbsp;
<center><math>V_0\,  {\mathcal{V}(\vec r,t)}  - \int_{V_0}^{V_0+\delta V} \,  P\, d \vec{r}=-P_0 \delta V- \frac{1}{2} \left( \frac{\partial P }{\partial V}\right)_0 \delta V^2+\ldots  </math> </center>
&nbsp;
where <math>\mathcal V(\vec r,t)</math>is the density of potential energy.


Generally speaking, a sound wave in an ideal gas oscillates sufficiently rapidly that heat is unable to flow fast enough to smooth out any temperature perturbations generated by the wave. Under these circumstances, the gas obeys the adiabatic gas law,  
However, Laplace undestood that a sound wave gas oscillates sufficiently rapidly that there is no time to thermalize. The heat is unable to flow fast enough to smooth out any temperature perturbations generated by the wave. Under these circumstances, the gas obeys the adiabatic gas law,  
<center><math>P  V^\gamma= </math> constant</center>
<center><math>P  V^\gamma= </math> constant</center>
where  <math>\gamma</math> the ratio of specific heats (i.e., the ratio of the gas's specific heat at constant pressure to its specific heat at constant volume). This ratio is approximately <math>1.4 </math> for ordinary air.
where  <math>\gamma</math> the ratio of specific heats (i.e., the ratio of the gas's specific heat at constant pressure to its specific heat at constant volume). This ratio is approximately <math>1.4 </math> for ordinary air.
* Show that the total potential energy, <math>W=\int \, d \vec{r} \, \mathcal V(\vec r,t)</math> writes
<center><math>  W= P_0 \int \, d \vec{r} \, \left( \sigma + \frac{\gamma}{2} \sigma^2\right)  </math> </center>
* Using the continuity equation of the gas, <math>\partial_t \rho=-\rho_0 \vec{\nabla} \cdot \partial_t \vec{u}(\vec{r},t)</math>,  show that  <math>  \sigma(\vec{r},t)= - \vec{\nabla} \cdot \vec{u}(\vec{r},t)  </math> and write the potential energy as a function of  <math> \vec{u}(\vec{r},t) </math>


===Lagrangian description===
'''Q13:''' Compute the bulk modulus and the sound speed predicted by Laplace.
* Show that the Lagrangian density writes
<center><math>  \mathcal{L} (\vec{r},t) = \frac{\rho_0}{2}  \dot{\vec{u}}^2 +  P_0 \vec{\nabla} \cdot \vec{u} -\frac{\gamma}{2} P_0 (\vec{\nabla} \cdot \vec{u})^2    </math></center>
* Show that the associated  equation of motion
<center><math>  \rho_0  \frac{\partial^2 \vec{u}}{\partial t^2}  -\gamma P_0  \vec{\nabla} \vec{\nabla} \cdot \vec{u}=0    </math></center>
* Using the continuity relation <math>  \sigma= - \vec{\nabla} \cdot \vec{u}  </math> show that the latter equation corresponds to the D'Alembert Equation for the scalar field <math>  \sigma  </math>
This scalar field behaves exaclty like an elastic scalar field.
* Determine the sound velocity.

Latest revision as of 13:29, 16 November 2019

Variational methods: Sound waves in solid and fluid materials

     

Consider a solid body or a fluid at rest. Under the action of an external force it will start to move or flow and the work done the force is transformed in kinetic energy. This is the case of a rigid body or an incompressible fluids, but in real materials part of the work can be used to induce a deformation. A compression for example has an ergetic cost both for fluids and solids, while a change in shape (shear) has a cost only for solids.

If the deformation is not too large the work is stored in terms of elastic energy and it is reversibly released when the force is removed. As a consequence, after a sudden pertubation, elastic waves propagates in the material. Similarly to light, which are waves associated to the electromagnetic field, the sound that we can ear are waves associated to the elastic field. But which field?

At variance with their electromagnetic cousins, elastic waves can propagate only inside materials and display a quite different nature in solids with respect to fluids. Here we derive their equations of motion in both kind of material and compute their speed.



Part I: Elasticity in solids

     

The first succesful attempt to describe deformations in solids is provided by the theory of elasticity. The theory is based on the assumptions that (1) the solid body can modeled as a continuum medium and (2) the energetic cost of the deformation is kept at the lowest order in perturbation. The fundamental equations of elasticity have been established by Cauchy and Poisson in the twenties of the 19th century, well before the discovery of the atomic structure of matter.

     

Displacement fields and strain tensor

     

Here we review the basic objects of elastic theory that you have done last year (e.g. see pages 62-66 of Mécanique du solide et des matérieaux, partie 1, Pascal Kurowski).


Consider a perfectly isotropic continuum medium with density mass at equilibrium:. Assume that at time a body is at rest and no external forces are applied. Each point of the body can be identified with its postion in the space:

Then under the action of external forces the body starts to be deformed: the point located in moves to a new location at time . The displacement, , differs from point to point of the body and is then a field, namely a function of the original position :

the displacement field encodes then all information about the deformation.

However large displacements does not always correspond to large deformation as the body can move rigidly without deformation. To quantify how much a body is deformed it is useful to introduce the symmetric strain tensor  :



Q1: Take two points at a distance and compute the distance after a small deformation. Show that at the lowest order in the deformation it can be written as


Compression: the (relative) density field

     

Consider now a local compression at the point . The volume element around the point, , is squeezed to a smaller volume and the density mass will locally increases from the uniform value :

The scalar field represents the relative fluctuation of the density.


Q2: Show that at the first order in perturbation one has

.

Tip: it is convenient to write the element volume in the principal coordinate around the point . There the symmetric deformation tensor is diagonal.

Conclude that


     


In general all deformation can be represented as the sum of a uniform compression (change in volume without change of shape) and a shear (change of shape without change of volume):

The first term is a shear as its trace is zero. The second term is a compression/rarefaction.

Energy cost of the deformation

   


A body at rest, in abscence of external force and at thermal equilibrium does not display any deformation, this means that when the strain tensor is zero for all points, the potential energy displays a minimum. As a consequence for small deformations the first terms of the expansion of the potential energy must be quadratic in the strain tensor (elastic approximation). The more general quadratic form can be written as , where the tensor contains all the elastic moduli. For an isotropic material the energy cost should be frame independent and we can write a simpler quadratic form that we will discuss in class:

The first term accounts for the cost of the change in volume, the second for the change of shape. The positive constants are respectively the bulk and the shear modulus and have dimensions of a pressure. These two constants are material dependent and fully describe its elastic properties.


   

Kinetic energy

   

The kinetic energy can then be written as

where is the mass density of the material at rest. Here used the fact that the mass contained in an infinitesimal volume around the point located in is .


   

Equation of motion with the variational principle

   

Q3: Show that the potential elastic energy can be re-written in the following form:


 


The associated action is given by

where is the Lagrangian density, is the kinetic energy density, and is the potential energy density


 

Q4: Write explicitly .

Q5: Using the variational methods show that the equation of motion for a given component of the displacement writes

Q6: Show that the 3 equations of motion take the form

and organize them in the vectorial form:

Q7: Provide the expression of the two constants To make progress we will consider plane waves, namely deformations that are fonction of only.

This means that all derivatives are zero.

Q8: Write the explicit form of the three wave equations. They are D'Alembert equations, explain why are called transverse mode velocity and longitudinal mode velocity.


 

It is possible to show that the result obtained for plain waves is very general: in solids elastic waves has two transverse components propagating at velocity and one longitudinal component propagating at velocity .

Conclude that the elastic field in fluids is the displacement vectorial field.


Elasticity in fluids

   

A fluid does not oppose a change in its shape with any internal resistance, but displays a finite energy cost to compression. Using the same reasoning used before we can write the Lagrangian density:

Q9 Show that the associated equation of motion

Q10 Show that the previous equation of motion corresponds to the D'Alembert Equation for the scalar field . Conclude that the elastic field in fluids is the scalar relative density field.



Sound speed in perfect gas

   

Generally speaking the sound speed (the transverse one for solids) takes the form

the constant K is much bigger in solid then liquids and much bigger in liquids then gases. For this reason sound propagates much faster in solids (6 km /s in steal) then in water (1 km /s) or, even worst, in air (331 m /s at T=273 K).


For perfect gases it is possible to evaluate the bulk modulus and then the speed sound velocity in gases. Newton did the first attempt, but he made a mistake corrected later by Laplace. Consider the gas at equilibrium at temperature , pressure and density . We consider a sudden expansion/compression from a volume around to and evaluate again the stored elastic energy. It can be written as the work associated to the expansion/compression:

the pressure can be expanded around the equlibrium


Q11: Show that

   


Newton idea was that the the compressed gas remain at the same temperature , so that

constant

Q12: Show that in this case

and using that at 1 atmosphere ( Pa) the density of air is kg/m (at T=273 K)) compute the sound speed predicted by Newton.

   

However, Laplace undestood that a sound wave gas oscillates sufficiently rapidly that there is no time to thermalize. The heat is unable to flow fast enough to smooth out any temperature perturbations generated by the wave. Under these circumstances, the gas obeys the adiabatic gas law,

constant

where the ratio of specific heats (i.e., the ratio of the gas's specific heat at constant pressure to its specific heat at constant volume). This ratio is approximately for ordinary air.

Q13: Compute the bulk modulus and the sound speed predicted by Laplace.