L-4: Difference between revisions

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\overline{Z_t[x_1] } =\int {\cal D} x_1 \exp\left[- \frac{1}{T} \int_0^t d \tau (\partial_\tau x)^2\right]  \overline{\exp\left[- \frac{1}{T} \int d \tau V(x,\tau ) \right]}
\overline{Z_t[x_1] } =\int {\cal D} x_1 \exp\left[- \frac{1}{T} \int_0^t d \tau (\partial_\tau x)^2\right]  \overline{\exp\left[- \frac{1}{T} \int d \tau V(x,\tau ) \right]}
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Note that the term <math>\overline{W^2} = \int d \tau_1 d\tau_2 \overline{V(x,\tau_1)V(x,\tau_2)}/T^2= D t \delta(0)/T^2</math> has a short distance divergence due to the delta-functiton, but is path independent. Hence we can write:
Note that the term <math> T^2 \overline{W^2} = \int d \tau_1 d\tau_2 \overline{V(x,\tau_1)V(x,\tau_2)}= D t \delta(0)</math> has a short distance divergence due to the delta-functiton. Hence we can write:
 
<center> <math>
\overline{Z_t[x_1] } =\int {\cal D} x_1 \exp\left[- \frac{1}{T} \int_0^t d \tau (\partial_\tau x)^2\right]  \exp\left[ \frac{D  t \delta(0)}{2T^2}  \right]}
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Revision as of 00:47, 5 January 2024

Goal 1: final lecture on KPZ and directed polymers at finite dimension. We will show that for a "glass transition" takes place.

Goal 2: We will mention some ideas related to glass transition in true glasses.


Part 1: KPZ in finite dimension

  • In we found and a glassy regime present at all temperatures. Moreover, the stationary solution tell us that is a Brownian motion in . However this solution does not identify the actual distribution of for a given . In particular we have no idea from where Tracy Widom comes from.
  • In the exponents are not known. There is an exact solution for the Caley tree (infinite dimension) that predicts a freezing transition to an 1RSB phase ().

Let's do replica!

To make progress in disordered systems we have to go through the moments of the partition function. We recall that

  • is a Gaussian field with
  • From the Wick theorem, for a generic Gaussian field we have

The first moment of the partition function is

Note that the term has a short distance divergence due to the delta-functiton. Hence we can write:

Failed to parse (syntax error): {\displaystyle \overline{Z_t[x_1] } =\int {\cal D} x_1 \exp\left[- \frac{1}{T} \int_0^t d \tau (\partial_\tau x)^2\right] \exp\left[ \frac{D t \delta(0)}{2T^2} \right]} }

Part 2: Structural glasses