T-2

Goal: derive the equilibrium phase diagram of the simplest spin-glass model, the Random Energy Model (REM).
Techniques: saddle point approximation, probability theory.

Problems

Problem 2: freezing transition & glassiness

In this Problem we compute the equilibrium phase diagram of the model, and in particular the quenched free energy density $f$ which controls the scaling of the typical value of the partition function, $Z\sim e^{-N\beta \,f+o(N)}$. We show that the free energy equals to

$f={\begin{cases}&-\left(T\log 2+{\frac {1}{2T}}\right)\quad {\text{if}}\quad T\geq T_{f}\\&-{\sqrt {2\,\log 2}}\quad {\text{if}}\quad T<T_{f}\end{cases}}\quad \quad T_{f}={\frac {1}{\sqrt {2\,\log 2}}}.$

At $T_{f}$ a transition occurs, often called freezing transition: in the whole low-temperature phase, the free-energy is “frozen” at the value that it has at the critical temperature $T=T_{f}$.
We also characterize the overlap distribution of the model: the overlap between two configurations ${\vec {\sigma }}^{\alpha },{\vec {\sigma }}^{\beta }$ is $q_{\alpha \,\beta }=N^{-1}\sum _{i=1}^{N}\sigma _{i}^{\alpha }\,\sigma _{i}^{\beta }$, and its distribution is

$P(q)=\sum _{\alpha ,\beta }{\frac {e^{-\beta E({\vec {\sigma }}^{\alpha })}}{Z}}{\frac {e^{-\beta E({\vec {\sigma }}^{\beta })}}{Z}}\delta (q-q_{\alpha \beta }).$

1. The freezing transition. The partition function the REM reads $Z=\sum _{\alpha =1}^{2^{N}}e^{-\beta E_{\alpha }}=\int dE\,{\mathcal {N}}(E)e^{-\beta E}.$ Using the behaviour of the typical value of ${\mathcal {N}}$ determined in Problem 1.1, derive the free energy of the model (hint: perform a saddle point calculation). What is the order of this thermodynamic transition?

2. Fluctuations, and back to average vs typical. Similarly to what we did for the entropy, one can define an annealed free energy $f_{\text{a}}$ from ${\overline {Z}}=e^{-N\beta f_{\text{a}}+o(N)}$: show that in the whole low-temperature phase this is smaller than the quenched free energy obtained above. Putting all the results together, justify why the average of the partition function in the low-T phase is "dominated by rare events".

3. Entropy catastrophe. What happens to the entropy of the model when the critical temperature is reached, and in the low temperature phase? What does this imply for the partition function $Z$?

4. Overlap distribution and glassiness. Justify why in the REM the overlap typically can take only values zero and one, leading to

   $P(q)=I_{2}\,\delta (q-1)+(1-I_{2})\,\delta (q),\quad \quad I_{2}={\frac {\sum _{\alpha }z_{\alpha }^{2}}{\left(\sum _{\alpha }z_{\alpha }\right)^{2}}},\quad \quad z_{\alpha }=e^{-\beta E_{\alpha }}$

   Why $I_{2}$ can be interpreted as a probability? Show that

   ${\overline {I_{2}}}={\begin{cases}0\quad &{\text{if}}\quad T>T_{f}\\1-{\frac {T}{T_{f}}}\quad &{\text{if}}\quad T\leq T_{f}\end{cases}}$

   and interpret the result. In particular, why is this consistent with the entropy catastrophe?
   

   Hint: For $T<T_{f}$, use that ${\overline {I_{2}}}={\frac {T_{f}}{T}}{\frac {d}{d\mu }}\log \int _{0}^{\infty }(1-e^{-u-\mu u^{2}})u^{-{\frac {T}{T_{f}}}-1}du{\Big |}_{\mu =0}$

Comment: the low-T phase of the REM is a frozen phase, characterized by the fact that the free energy is temperature independent, and that the typical value of the partition function is very different from the average value. In fact, the low-T phase is also a glass phase with $q_{EA}=1$. This is also a phase where a peculiar symmetry, the so called replica symmetry, is broken. We go back to this concepts in the next sets of problems.

Check out: key concepts

Freezing transition, entropy catastrophe, condensation, overlap distribution.