T-4: Difference between revisions

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=== Problem 4.1: the susceptibilities ===
=== Problem 4.1: the susceptibilities ===
 
In this problem, we consider the magnetic susceptibilities. In an Ising system, the thermodynamic magnetic susceptibility is
Consider the mean field Ising model. Let <math> m(\beta,h)</math> be the magnetization at inverse temperature <math> \beta</math> and field <math> h</math>, which satisfies <math> m= tanh[\beta(h+m)]</math>. For finite N, behaves as [plot].
 
Define the thermodynamic magnetic susceptibility susceptibility
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<math>
<math>
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</math>
</math>
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where <math> m(\beta,h)=\lim_{N \to \infty} m_N(\beta,h)</math> is the magnetization at inverse temperature <math> \beta</math> and external field <math> h</math>, and <math> m_N(\beta,h)</math> its finite-size counterpart. By the Fluctuation Dissipation relation, we also know that
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<math>
\chi_N(\beta)= \frac{d m_N(\beta, h)}{dh} \Big|_{h=0}= \frac{\beta}{N}\sum_{ij} \langle \sigma_i \sigma_j \rangle_{c} =\frac{\beta}{N}\sum_{ij} \left(\langle \sigma_i \sigma_j \rangle- \langle \sigma_i \rangle \langle \sigma_j \rangle \right).
</math>
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Consider the mean field Ising model. Let , which satisfies <math> m= tanh[\beta(h+m)]</math>. For finite N, behaves as [plot].
Define the
where assumed that <math> N \to \infty</math> before <math> h \to 0</math>.  
where assumed that <math> N \to \infty</math> before <math> h \to 0</math>.  
  Show that  
  Show that  
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The susceptibility at finite N is given by FDT
The susceptibility at finite N is given by FDT
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<math>
\chi_N(\beta)= \frac{d m_N(\beta, h)}{dh} \Big|_{h=0}= \frac{\beta}{N}\sum_{ij} \langle \sigma_i \sigma_j \rangle_{c}
</math>
</center>
In the ferromagnet, using that <math>\overline{\langle \sigma_i \sigma_j \rangle_c}= m^2</math> show divergence. In a spin glass, by symmetry with respect to sign flips of the couplings, it holds <math>\overline{\langle \sigma_i \sigma_j \rangle_c}= 0</math> for  <math> i \neq j  </math>. Show that  
In the ferromagnet, using that <math>\overline{\langle \sigma_i \sigma_j \rangle_c}= m^2</math> show divergence. In a spin glass, by symmetry with respect to sign flips of the couplings, it holds <math>\overline{\langle \sigma_i \sigma_j \rangle_c}= 0</math> for  <math> i \neq j  </math>. Show that  
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Revision as of 19:42, 24 December 2023

Goal of these problems:


Key concepts:


The free-energy landscape of the SK model

We have seen an example of mean-field model, the spherical p-spin, in which the low-T phase is glassy, described by a 1-RSB ansatz of the overlap matrix. The thermodynamics in the glassy phase is described by three quantities: the typical overlap between configurations belonging to the same pure state, the typical overlap between configurations belonging to different pure states, and the probability that two configurations extracted at equilibrium belong to the same state. It can be shown that the low-T, frozen phase of the REM is also described by this 1-RSB ansatz with and . Replicas are a way to explore the structure of the free-energy landscape.


The Sherrington-Kirkpatrick model introduced in Lecture 1 also has a low-T phase that is glassy. However, the structure of the free-energy landscape is more complicated the mutual overlaps between equilibrium states are organized in a complicated pattern. To understand it, let us consider a 2-RSB ansatz for the overlap matrix:

which assumes that replicas are split into blocks, and that inside each block they are further split into blocks (in the example above,). This is also not the correct structure for the SK model. The correct one obtained iterating this procedure an infinite number of times, as understood by Parisi in his seminal paper of XX. One ends up with a series of overlaps with . The underlying picture of the free-energy landscape is as follows: equilibrium states have self-overlap . They are arranged in clusters such that states inside a cluster have overlap , but such clusters are arranged in other clusters at a higher level, at mutual overlap and so on. In the limit , the overlap distribution becomes a continuous function.

Problem 4.1: the susceptibilities

In this problem, we consider the magnetic susceptibilities. In an Ising system, the thermodynamic magnetic susceptibility is

where is the magnetization at inverse temperature and external field , and its finite-size counterpart. By the Fluctuation Dissipation relation, we also know that


Consider the mean field Ising model. Let , which satisfies . For finite N, behaves as [plot].

Define the

where assumed that before .

Show that 

Finite for , , this quantity diverges. Consider now . The quantity above assumes that N is infinity before h to zero. looking at the graph, Show that the limits and that one is taking to get the susceptibility do not commute: if is taken first, the system remains trapped in the pure state selected by h, and the susceptibility when remains finite; if instead before, the susceptibility is proportional to N and so it diverges.


The susceptibility at finite N is given by FDT

In the ferromagnet, using that show divergence. In a spin glass, by symmetry with respect to sign flips of the couplings, it holds for . Show that

</math>

Show that this quantity does not diverge at the spin glass transition.


The interpretation of the susceptibility is one would measure if the system is prepared at equilibrium, then a small magnetic field is applied and the new equilibrium state is reached. you let the system reach the best free energy states in presence of the field: This is called field-cooled.


What would be the susceptibility that measures the response of the system within a given state? Could you explain why