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Created page with "= Exercise 2: Edwards-Wilkinson Interface with Stationary Initial Condition (7.5 points) = Consider an Edwards-Wilkinson interface in 1+1 dimensions, at temperature <math>T</math>, and of length <math>L</math> with periodic boundary conditions: <center><math> \frac{\partial h(x,t)}{\partial t} = \nu \nabla^2 h(x,t) + \eta(x,t) </math></center> where <math>\eta(x,t)</math> is a Gaussian white noise with zero mean and variance: <center><math> \langle \eta(x,t) \eta(x',..."
 
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= Exercise 2: Edwards-Wilkinson Interface with Stationary Initial Condition (7.5 points) =
= Exercise 2: Edwards-Wilkinson Interface with Stationary Initial Condition =


Consider an Edwards-Wilkinson interface in 1+1 dimensions, at temperature <math>T</math>, and of length <math>L</math> with periodic boundary conditions:
Consider an Edwards-Wilkinson interface in 1+1 dimensions, at temperature <math>T</math>, and of length <math>L</math> with periodic boundary conditions:
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where <math>q = 2 \pi n / L, \; n = \ldots, -1, 0, 1, \ldots</math>.
where <math>q = 2 \pi n / L, \; n = \ldots, -1, 0, 1, \ldots</math>.


In class, you computed the mean square displacement of a point <math>h(x,t)</math> starting from a flat interface at <math>t=0</math>, i.e., <math>h(x,0) = 0</math>. The result was:
In class, we computed the width of the interface starting from a flat interface at <math>t=0</math>, i.e., <math>h(x,0) = 0</math>.  The mean square displacement of a point <math>h(x,t)</math> is similar but includes also the contribution of the zero mode. The result is:


<center><math>
<center><math>

Revision as of 13:52, 31 August 2025

Exercise 2: Edwards-Wilkinson Interface with Stationary Initial Condition

Consider an Edwards-Wilkinson interface in 1+1 dimensions, at temperature T, and of length L with periodic boundary conditions:

∂h(x,t)∂t=ν∇2h(x,t)+η(x,t)

where η(x,t) is a Gaussian white noise with zero mean and variance:

⟨η(x,t)η(x′,t′)⟩=2Tδ(x−x′)δ(t−t′)

The solution can be written in Fourier space as:

h^q(t)=h^q(0)e−νq2t+∫0tdse−νq2(t−s)ηq(s)

with Fourier decomposition:

h^q(t)=1L∫0Leiqxh(x,t),h(x,t)=∑qe−iqxh^q(t),⟨ηq1(t′)ηq2(t)⟩=2TLδq1,−q2δ(t−t′)

where q=2πn/L,n=…,−1,0,1,….

In class, we computed the width of the interface starting from a flat interface at t=0, i.e., h(x,0)=0. The mean square displacement of a point h(x,t) is similar but includes also the contribution of the zero mode. The result is:

⟨Δhflat2⟩=2TLt+{T2tπν,t≪L2,TνL12,t≫L2.

The first term describes the diffusion of the center of mass, while the second comes from the non-zero Fourier modes.

Now consider the case where the initial interface h(x,0) is drawn from the equilibrium distribution at temperature T:

Pstat.[h]∝exp⁡[−ν2T∫0Ldx(∂xh)2]

For simplicity, set the initial center of mass to zero: h^q=0(0)=0. We consider the mean square displacement of the point h(x=0,t). The average is performed over both the thermal noise ⟨⋅⟩ and the initial condition ⋅‾:

⟨Δh2⟩‾=⟨[h(0,t)−h(0,0)]2⟩‾=⟨h2(0,t)⟩‾+⟨h2(0,0)⟩‾−2⟨h(0,t)h(0,0)⟩‾

Questions:

  1. Compute the ensemble average of the Gaussian initial condition:
h^q1(0)h^q2(0)‾
  • Hint:* Write the integral in terms of Fourier modes and use ∫0Ldxeiqx=Lδq,0.
  1. Show that:
⟨h2(0,0)⟩‾=TνL∑q≠01q2,⟨h(0,t)h(0,0)⟩‾=TνL∑q≠0e−νq2tq2
  1. Show that:
⟨h2(0,t)⟩‾=A+⟨Δhflat2⟩

where the term A depends only on the initial condition. Show that:

A(t)=TνL∑q≠0e−2νq2tq2
  1. Hence write:
C(t)≡⟨Δh2⟩‾−⟨Δhflat2⟩=2TνL∑n=1∞(1−e−ν(2πn/L)2t)2(2πn/L)2

Estimate C(t) for t≫L2.

  1. Estimate C(t) for t≪L2 and large L.
  • Hint:* Write the series as an integral using the continuum variable z=2πn/L. It is helpful to know:
∫0∞ds(1−e−s2)2s2=π(2−2)

Provide the two asymptotic behaviors of ⟨Δh2⟩‾.