L-3: Difference between revisions

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This relation is actually exact also for the continuum model.
This relation is actually exact also for the continuum model.


==Back to the continuum model==
=Directed polymers in the continuum=
We now reanalyze the previous problem in the presence of quenched disorder. 
Instead of discussing the case of interfaces, we will focus on directed polymers. 
Let us consider polymers <math>x(\tau)</math> of length <math>t</math>. 
The energy associated with a given polymer configuration can be written as 
<center>
<math>
E[x(\tau)] = \int_0^t d\tau \, \left[ \frac{1}{2} \left( \frac{dx}{d\tau} \right)^2 + V(x(\tau), \tau) \right]
</math>
</center>
The first term describes the elastic energy of the polymer, 
while the second one is the disordered potential, which we assume to be 
<center>
<math>
\overline{ V(x,\tau) } = 0, \qquad
\overline{ V(x,\tau) V(x',\tau') } = D \, \delta(x-x') \, \delta(\tau-\tau') .
</math>
</center>
where 'D' is the disorder strength.


Let us consider polymers <math>
 
x(\tau) </math>  of length  <math>
== Polymer partition function and propagator of a quantum particle==
t </math>, starting in  <math>0 </math> and ending in <math>x </math> and at thermal equlibrium at  temperature <math>T</math>. The partition function of the model writes as  
 
Let us consider polymers starting in  <math>0 </math>, ending in <math>x </math> and at thermal equilibrium at  temperature <math>T</math>. The partition function of the model writes as  
<center> <math>
<center> <math>
Z(x,t) =\int_{x(0)=0}^{x(t)=x} {\cal D} x(\tau) \exp\left[- \frac{1}{T} \int_0^t d \tau \frac{1}2(\partial_\tau x)^2 +V(x(\tau),\tau)\right]
Z(x,t) =\int_{x(0)=0}^{x(t)=x} {\cal D} x(\tau) \exp\left[- \frac{1}{T} \int_0^t d \tau \frac{1}2(\partial_\tau x)^2 +V(x(\tau),\tau)\right]
</math></center>
</math></center>
For simplicity, we assume a white noise, <math> \overline{V(x,\tau) V(x',\tau')} = D \delta(x-x') \delta(\tau-\tau') </math>. Here, the partition function is written as a sum over all possible paths, corresponding to all possible polymer configurations that start at <math>0</math> and end at <math>x</math>, weighted by the appropriate Boltzmann factor.
Here, the partition function is written as a sum over all possible paths, corresponding to all possible polymer configurations that start at <math>0</math> and end at <math>x</math>, weighted by the appropriate Boltzmann factor.


=== Polymer partition function and propagator of a quantum particle===


Let's perform the following change of variables: <math>\tau=i t' </math>. We also identifies <math>T</math> with <math>\hbar</math> and <math> \tilde t= -i t </math> as the time.
Let's perform the following change of variables: <math>\tau=i t' </math>. We also identifies <math>T</math> with <math>\hbar</math> and <math> \tilde t= -i t </math> as the time.
Line 73: Line 91:
From the Feymann path integral formulation, <math> Z[x,\tilde t]</math>  is the propagator of the quantum particle.  
From the Feymann path integral formulation, <math> Z[x,\tilde t]</math>  is the propagator of the quantum particle.  


=== Feynman-Kac formula===
Let's derive the Feyman Kac formula for  <math>Z(x,t)</math> in the general case:
* First, focus on free paths and introduce the following probability
<center> <math>
P[A,x,t] =\int_{x(0)=0}^{x(t)=x} {\cal D} x(\tau) \exp\left[- \frac{1}{T} \int_0^t d \tau \frac{1}2(\partial_\tau x)^2 \right] \delta\left(  \int_0^t d \tau V(x(\tau),\tau)-A \right)
</math></center>
* Second, the moments generating function
<center> <math>
Z_p(x ,t) = \int_{-\infty}^\infty d A e^{-p A} P[A,x,t] =\int_{x(0)=0}^{x(t)=x} {\cal D} x(\tau) e^{-\frac{1}{T} \int_0^t d \tau \frac{1}2(\partial_\tau x)^2  -p \int_0^t d \tau  V(x(\tau),\tau)}
</math></center>
* Third, consider free paths evolving up to <math>t+dt</math> and reaching <math>x</math> :
<center> <math>
Z_p(x,t+dt)= \left\langle e^{-p \int_0^{t+dt} d \tau  V(x(\tau),\tau)}\right\rangle=  \left\langle e^{-p \int_0^{t} d \tau  V(x(\tau),\tau)}\right\rangle e^{-p V(x,t) d t } =[1 -p V(x,t) d t +\dots]\left\langle Z_p(x-\Delta x,t) \right\rangle_{\Delta x}
</math></center>
Here  <math>  \langle \ldots \rangle</math> is the average over all free paths, while  <math>  \langle \ldots \rangle_{\Delta x}</math> is the average over the last jump, namely  <math>  \langle \Delta x \rangle=0
</math> and  <math>  \langle \Delta x^2 \rangle=T d t  </math>.
* At the lowest order we have
<center> <math>
Z_p(x,t+dt)= Z_p(x,t) +dt \left[ \frac{T}{2} \partial_x^2 Z_p -p V(x,t) Z_p \right] +O(dt^2)
</math></center>
Replacing <math> p=1/T</math> we obtain the partition function is the solution of the Schrodinger-like equation:
<center> <math>
\partial_t Z(x,t) =-  \hat H Z = - \left[ -\frac{T}{2}\frac{d^2 }{d x^2} + \frac{V(x,\tau)}{T}\right] Z(x,t)
</math>
<math>
Z[x,t=0]=\delta(x)
</math>
</center>
===Remarks===
<Strong>Remark 1:</Strong>
This equation is a diffusive equation with multiplicative noise <math>V(x,\tau)/T</math> . Edwards Wilkinson is instead a diffusive equation with additive noise.
<Strong>Remark 2:</Strong>
This hamiltonian is time dependent because of the multiplicative noise <math>V(x,\tau)/T</math>. For a <Strong> time independent </Strong> hamiltonian, we can use the spectrum of the operator. In general we will have to parts:
* A discrete set of eigenvalues <math>E_n</math> with the eigenstates <math>\psi_n(x)</math>
* A continuum part where the states <math>\psi_E(x)</math> have energy <math>E</math>. We define the density of states  <math>\rho(E)</math>, such that the number of states with energy in (<math>E, E + dE</math>) is <math>\rho(E) dE </math>.
In this case <math> Z[x,t] </math> can be written has the sum of two contributions:
<center> <math>
Z[x,t] = \left( e^{- \hat H t} \right)_{0 \to x}= \sum_n \psi_n(0) \psi_n^*(x) e^{- E_n t} + \int_0^\infty dE \, \rho(E) \psi_E(0) \psi_E^*(x) e^{- E t}.
</math>
</center>
In absence of disorder, one can find the propagator of the free particle, that, in the original variables, writes:
In absence of disorder, one can find the propagator of the free particle, that, in the original variables, writes:
<center> <math>
<center> <math>

Revision as of 10:45, 31 January 2026

Goal: This lecture is dedicated to a classical model in disordered systems: the directed polymer in random media. It has been introduced to model vortices in superconductur or domain wall in magnetic film. We will focus here on the algorithms that identify the ground state or compute the free energy at temperature T, as well as, on the Cole-Hopf transformation that map this model on the KPZ equation.

Directed Polymers (d = 1)

The configuration is described by a vector function: x(t), where t is the internal coordinate. The polymer lives in D=1+N dimensions.

Examples: vortex lines, DNA strands, fronts.

Although polymers may form loops, we restrict to directed polymers, i.e., configurations without overhangs or backward turns.

Directed Polymers on a lattice

Sketch of the discrete Directed Polymer model. At each time the polymer grows either one step left either one step right. A random energy V(τ,x) is associated at each node and the total energy is simply E[x(τ)]=τ=0tV(τ,x).


We introduce a lattice model for the directed polymer (see figure). In a companion notebook we provide the implementation of the powerful Dijkstra algorithm. Dijkstra allows to identify the minimal energy among the exponential number of configurations x(τ)

Emin=minx(τ)E[x(τ)].

We are also interested in the ground state configuration xmin(τ). For both quantities we expect scale invariance with two exponents θ,ζ for the energy and for the roughness

Emin=ct+κ1tθχ,xmin(t/2))κ2tζχ~

Universal exponents: Both θ,ζ are Independent of the lattice, the disorder distribution, the elastic constants, or the boudanry conditions.

Non-universal constants: c,κ1,κ2 are of order 1 and depend on the lattice, the disorder distribution, the elastic constants... However c is independent on the boudanry conditions!

Universal distributions: χ,χ~ are instead universal, but depends on the boundary condtions. Starting from 2000 a magic connection has been revealed between this model and the smallest eigenvalues of random matrices. In particular I discuss two different boundary conditions:

  • Droplet: x(τ=0)=x(τ=t)=0. In this case, up to rescaling, χ is distributed as the smallest eigenvalue of a GUE random matrix (Tracy Widom distribution F2(χ))
  • Flat: x(τ=0)=0 while the other end x(τ=t) is free. In this case, up to rescaling, χ is distributed as the smallest eigenvalue of a GOE random matrix (Tracy Widom distribution F1(χ))

Entropy and scaling relation

It is useful to compute the entropy

Entropy=ln(ttx2)tln2x22t+O(x4)

From which one could guess from dimensional analysis

θ=2ζ1

This relation is actually exact also for the continuum model.

Directed polymers in the continuum

We now reanalyze the previous problem in the presence of quenched disorder. Instead of discussing the case of interfaces, we will focus on directed polymers. Let us consider polymers x(τ) of length t. The energy associated with a given polymer configuration can be written as

E[x(τ)]=0tdτ[12(dxdτ)2+V(x(τ),τ)]

The first term describes the elastic energy of the polymer, while the second one is the disordered potential, which we assume to be

V(x,τ)=0,V(x,τ)V(x,τ)=Dδ(xx)δ(ττ).

where 'D' is the disorder strength.


Polymer partition function and propagator of a quantum particle

Let us consider polymers starting in 0, ending in x and at thermal equilibrium at temperature T. The partition function of the model writes as

Z(x,t)=x(0)=0x(t)=x𝒟x(τ)exp[1T0tdτ12(τx)2+V(x(τ),τ)]

Here, the partition function is written as a sum over all possible paths, corresponding to all possible polymer configurations that start at 0 and end at x, weighted by the appropriate Boltzmann factor.


Let's perform the following change of variables: τ=it. We also identifies T with and t~=it as the time.

Z(x,t~)=x(0)=0x(t~)=x𝒟x(t)exp[i0t~dt12(tx)2V(x(t),t)]

Note that S[x]=0t~dt12(tx)2V(x(t),t) is the classical action of a particle with kinetic energy 12(τx)2 and time dependent potential V(x(τ),τ), evolving from time zero to time t~. From the Feymann path integral formulation, Z[x,t~] is the propagator of the quantum particle.


Feynman-Kac formula

Let's derive the Feyman Kac formula for Z(x,t) in the general case:

  • First, focus on free paths and introduce the following probability
P[A,x,t]=x(0)=0x(t)=x𝒟x(τ)exp[1T0tdτ12(τx)2]δ(0tdτV(x(τ),τ)A)
  • Second, the moments generating function
Zp(x,t)=dAepAP[A,x,t]=x(0)=0x(t)=x𝒟x(τ)e1T0tdτ12(τx)2p0tdτV(x(τ),τ)
  • Third, consider free paths evolving up to t+dt and reaching x :
Zp(x,t+dt)=ep0t+dtdτV(x(τ),τ)=ep0tdτV(x(τ),τ)epV(x,t)dt=[1pV(x,t)dt+]Zp(xΔx,t)Δx

Here is the average over all free paths, while Δx is the average over the last jump, namely Δx=0 and Δx2=Tdt.

  • At the lowest order we have
Zp(x,t+dt)=Zp(x,t)+dt[T2x2ZppV(x,t)Zp]+O(dt2)

Replacing p=1/T we obtain the partition function is the solution of the Schrodinger-like equation:

tZ(x,t)=H^Z=[T2d2dx2+V(x,τ)T]Z(x,t)

Z[x,t=0]=δ(x)

Remarks

Remark 1:

This equation is a diffusive equation with multiplicative noise V(x,τ)/T . Edwards Wilkinson is instead a diffusive equation with additive noise.

Remark 2: This hamiltonian is time dependent because of the multiplicative noise V(x,τ)/T. For a time independent hamiltonian, we can use the spectrum of the operator. In general we will have to parts:

  • A discrete set of eigenvalues En with the eigenstates ψn(x)
  • A continuum part where the states ψE(x) have energy E. We define the density of states ρ(E), such that the number of states with energy in (E,E+dE) is ρ(E)dE.

In this case Z[x,t] can be written has the sum of two contributions:

Z[x,t]=(eH^t)0x=nψn(0)ψn*(x)eEnt+0dEρ(E)ψE(0)ψE*(x)eEt.

In absence of disorder, one can find the propagator of the free particle, that, in the original variables, writes:

Zfree(x,t)=ex2/(2Tt)2πTt

Feynman-Kac formula

Let's derive the Feyman Kac formula for Z(x,t) in the general case:

  • First, focus on free paths and introduce the following probability
P[A,x,t]=x(0)=0x(t)=x𝒟x(τ)exp[1T0tdτ12(τx)2]δ(0tdτV(x(τ),τ)A)
  • Second, the moments generating function
Zp(x,t)=dAepAP[A,x,t]=x(0)=0x(t)=x𝒟x(τ)e1T0tdτ12(τx)2p0tdτV(x(τ),τ)
  • Third, the backward approach. Consider free paths evolving up to t+dt and reaching x :
Zp(x,t+dt)=ep0t+dtdτV(x(τ),τ)=ep0tdτV(x(τ),τ)epV(x,t)dt=[1pV(x,t)dt+]Zp(xΔx,t)Δx

Here is the average over all free paths, while Δx is the average over the last jump, namely Δx=0 and Δx2=Tdt.

  • At the lowest order we have
Zp(x,t+dt)=Zp(x,t)+dt[T2x2ZppV(x,t)Zp]+O(dt2)

Replacing p=1/T we obtain the partition function is the solution of the Schrodinger-like equation:

tZ(x,t)=H^Z=[T2d2dx2+V(x,τ)T]Z(x,t)

Z[x,t=0]=δ(x)

Remarks

Remark 1:

This equation is a diffusive equation with multiplicative noise. Edwards Wilkinson is instead a diffusive equation with additive noise. The Cole Hopf transformation allows to map the diffusive equation with multiplicative noise in a non-linear equation with additive noise. We will apply this tranformation and have a surprise.

Remark 2: This hamiltonian is time dependent because of the multiplicative noise V(x,τ)/T. For a time independent hamiltonian, we can use the spectrum of the operator. In general we will have to parts:

  • A discrete set of eigenvalues En with the eigenstates ψn(x)
  • A continuum part where the states ψE(x) have energy E. We define the density of states (DOS) ρ(E), such that the number of states with energy in (E,E+dE) is ρ(E)dE.

In this case Z[x,t] can be written has the sum of two contributions:

Z[x,t]=(eH^t)0x=nψn(0)ψn*(x)eEnt+0dEρ(E)ψE(0)ψE*(x)eEt.

Exercise: free particle in 1D

  • Step 1: The spectrum

For a free particle there a no discrete eigenvalue, but only a continuum spectrum. In 1D the hamiltonian is H^=(T/2)x2. Show that the continuum spectrum has the form

ψk(x)=12πeikx,withEk=Tk22

Here k is a real number, while Ek is a positive number. Note that the states are delocalized on the entire real axis and they cannot be normalized to unit but you impose the Dirac delta normalization:

dxψk*(x)ψk(x)=δ(kk)
  • Step 2: the DOS

For a given energy E there are two states

ψE(x)=12πei2E/Tx,and,ψE+(x)=12πei2E/Tx

Use the definition of DOS

ρ(E)=dkδ(EEk)

ans show that for both

ψE(x),ψE(x)

you have  :

ρ(E)=12ET
  • Step 3: the propagator

Use the spectral decomposition of the propagator to recover Zfree(x,t). Tip: use dxexp[(ax2+bx)]=π/aexp[b2/(4a)].

Cole Hopf Transformation

Replacing

  • T=2ν
  • x=r
  • Z(x,t)=exp(λ2νh(r,t))
  • V(x,t)=λη(r,t)

You get

th(r,t)=ν2h(r,t)+λ2(h)2+η(r,t)

The KPZ equation!

We can establish a KPZ/Directed polymer dictionary, valid in any dimension. Let us remark that the free energy of the polymer is

F=TlnZ(x,t)=1λh(r,t)

At low temperature, the free energy approaches the ground state energy, Emin.

Dictionary
KPZ KPZ exponents Directed polymer Directed polymer exponents
r rt1/z x xtζ
t h(r,t)tα/z t
h h(r,t)rα F,Emin (EminEmin)2t2θ

We conclude that

θ=α/z,ζ=1/z

Moreover, the scaling relation θ=2ζ1 is a reincarnation of the Galilean invariance α+z=2.