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Introduction: Interfaces and Directed Polymers
The physical properties of many materials are governed by manifolds embedded in them. Examples include: dislocations in crystals, domain walls in ferromagnets or vortex lines in superconductors. We fix the following notation:
- <math>D</math>: spatial dimension of the embedding medium
– <math>d</math>: internal dimension of the manifold
– <math>N</math>: dimension of the displacement (or height) field
These satisfy the relation:
<center><math>D = d + N</math></center>
We focus on two important cases:
=== Directed Polymers (<math>d = 1</math>)===
The configuration is described by a vector function:
<math>\vec{x}(t)</math>,
where <math>t</math> is the internal coordinate. The polymer lives in <math>D = 1 + N</math> dimensions.
Examples: vortex lines, DNA strands,  fronts.
Although polymers may form loops, we restrict to directed polymers, i.e., configurations without overhangs or backward turns.
===Interfaces (<math>N = 1</math>)===
The interface is described by a scalar height field:
<math>h(\vec{r}, t)</math>,
where <math>\vec{r} \in \mathbb{R}^d</math> is the internal coordinate and <math>t</math> represents time. Again, Introduction: Interfaces and Directed Polymers
=Interfaces: thermal shaking  =
=Interfaces: thermal shaking  =



Revision as of 15:12, 7 August 2025

Introduction: Interfaces and Directed Polymers

The physical properties of many materials are governed by manifolds embedded in them. Examples include: dislocations in crystals, domain walls in ferromagnets or vortex lines in superconductors. We fix the following notation: - D: spatial dimension of the embedding medium – d: internal dimension of the manifold – N: dimension of the displacement (or height) field

These satisfy the relation:

D=d+N

We focus on two important cases:

Directed Polymers (d=1)

The configuration is described by a vector function: x(t), where t is the internal coordinate. The polymer lives in D=1+N dimensions. Examples: vortex lines, DNA strands, fronts. Although polymers may form loops, we restrict to directed polymers, i.e., configurations without overhangs or backward turns.

Interfaces (N=1)

The interface is described by a scalar height field: h(r,t), where rd is the internal coordinate and t represents time. Again, Introduction: Interfaces and Directed Polymers



Interfaces: thermal shaking

Consider domain wall h(r,t) fluctuating at equilibrium at the temperature T. Here t is time, r defines the d-dimensional coordinate of the interface and h is the scalar height field. Hence, the domain wall separating two phases in a film has d=1,r, in a solid instead d=2,r𝟐.

Two assumptions are done:

  • Overhangs, pinch-off are neglected, so that h(r,t) is a scalar univalued function.
  • The dynamics is overdamped, so that we can neglect the inertial term.

Derivation

The Langevin equation of motion is

th(r,t)=μδEpotδh(r,t)+η(r,t)

The first term δEpot/δh(r,t) is the elastic force trying to smooth the interface, the mobility μ is the inverse of the viscosity. The second term is the Langevin noise. It is Guassian and defined by

η(r,t)=0,η(r,t)η(r,t)=2dDδd(rr)δ(tt)

The symbol indicates the average over the thermal noise and the diffusion constant is fixed by the Einstein relation D=μKBT. We set μ=KB=1

The potential energy of surface tension (ν is the stiffness) can be expanded at the lowest order in the gradient:

Epot=νddr1+(h)2const.+ν2ddr(h)2

Hence, we have the Edwards Wilkinson equation:

th(r,t)=ν2h(r,t)+η(r,t)

Scaling Invariance

The equation enjoys of a continuous symmetry because h(r,t) and h(r,t)+c cannot be distinguished. This is a condition of scale invariance:

h(br,bzt)inlawbαh(r,t)

Here z,α are the dynamic and the roughness exponent respectively. From dimensional analysis

bαzth(r,t)=bα22h(r,t)+bd/2z/2η(r,t)

From which you get z=2 in any dimension and a rough interface below d=2 with α=(2d)/2.

Explicit Solution

For simplicity, consider a 1-dimensional line of size L with periodic boundary conditions. It is useful to introduce the Fourier modes:

h^q(t)=1L0Leiqrh(r,t),h(r,t)=qeiqrh^q(t)

Here q=2πn/L,n=,1,0,1, and recall 0Ldreiqr=Lδq,0.

  • Show that the EW equation writes
th^q(t)=νq2h^q(t)+ηq(t),withηq1(t)ηq2(t)=2TLδq1,q2δ(tt)

The solution of this first order linear equation writes

h^q(t)=h^q(0)eνq2t+0tdseνq2(ts)ηq(s)

Assume that the interface is initially flat, namely h^q(0)=0.

  • Compute the width h(x,t)2=qhq(t)hq(t). Comment about the roughness and the short times growth.