TBan-II: Difference between revisions

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\theta=2 \zeta-1
\theta=2 \zeta-1
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We will see that this relation is actually exact.
This relation is actually exact also for the continuum model.

Revision as of 20:28, 30 August 2025

Dijkstra Algorithm and transfer matrix

Sketch of the discrete Directed Polymer model. At each time the polymer grows either one step left either one step right. A random energy V(τ,x) is associated at each node and the total energy is simply E[x(τ)]=τ=0tV(τ,x).


We introduce a lattice model for the directed polymer (see figure). In a companion notebook we provide the implementation of the powerful Dijkstra algorithm.

Dijkstra allows to identify the minimal energy among the exponential number of configurations x(τ)

Emin=minx(τ)E[x(τ)].

We are also interested in the ground state configuration xmin(τ). For both quantities we expect scale invariance with two exponents θ,ζ for the energy and for the roughness

Emin=ct+btθχ,xmin(t/2))atζχ~

Universal exponents: Both θ,ζ are Independent of the lattice, the disorder distribution, the elastic constants, or the boudanry conditions. Note that ω=θ, while for an interface ω=dθ.

Non-universal constants: c,b,a are of order 1 and depend on the lattice, the disorder distribution, the elastic constants... However c is independent on the boudanry conditions!

Universal distributions: χ,χ~ are instead universal, but depends on the boundary condtions. Starting from 2000 a magic connection has been revealed between this model and the smallest eigenvalues of random matrices. In particular I discuss two different boundary conditions:

  • Droplet: x(τ=0)=x(τ=t)=0. In this case, up to rescaling, χ is distributed as the smallest eigenvalue of a GUE random matrix (Tracy Widom distribution F2(χ))
  • Flat: x(τ=0)=0 while the other end x(τ=t) is free. In this case, up to rescaling, χ is distributed as the smallest eigenvalue of a GOE random matrix (Tracy Widom distribution F1(χ))

Entropy and scaling relation

It is useful to compute the entropy

Entropy=ln(ttx2)tln2x2t+O(x4)

From which one could guess from dimensional analysis

θ=2ζ1

This relation is actually exact also for the continuum model.