L-2: Difference between revisions

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b^{\alpha-z} \partial_t h(r,t)= b^{\alpha-2} \nabla^2 h(r,t) +b^{-d/2-z/2} \eta(r,t)
b^{\alpha-z} \partial_t h(r,t)= b^{\alpha-2} \nabla^2 h(r,t) +b^{-d/2-z/2} \eta(r,t)
</math></center>
</math></center>
From which you get <math> z=2 </math> in any dimension and a rough interface below <math> d=2 </math> with <math> \alpha =(2-d)/2 </math>
From which you get <math> z=2 </math> in any dimension and a rough interface below <math> d=2 </math> with <math> \alpha =(2-d)/2 </math>.
 
=== Exercise L2-A: Solve Edward-Wilkinson ===
=== Exercise L2-A: Solve Edward-Wilkinson ===
For simplicity, consider a line of size L with periodic boundary conditions. It is useful to introduce the Fourier modes:
 
For simplicity, consider a 1-dimensional line of size L with periodic boundary conditions. It is useful to introduce the Fourier modes:
<center> <math>
\hat h_q(t)= \frac{1}{L} \int_0^L e^{iqr} h(r,t), \quad h(r,t)= \sum_q e^{-iqr} \hat h_q(t)
</math></center>
Here <math> q=2 \pi n/L, n=\ldots ,-1,0,1,\ldots</math> and recall <math> \int_0^L d r e^{iqr}= L \delta_{q,0} </math>.
*  Show that the EW equation writes
<center> <math>
\partial_t \hat h_q(t)= -\mu \sigma q^2 \hat h_q(t)+ \eta_q(t), \quad \text{with} \; \langle \eta_{q_1}(t')  \eta_{q_2}(t)\rangle =\frac{D}{L} \delta_{q_1,-q2}\delta(t-t') 
</math></center>
 
The solution of this first order linear equation writes
<center> <math>
\hat h_q(t)= \hat h_q(0) +\int_0^t d s e^{-\mu \sigma q^2 s} \eta_q(s)
</math></center>
Assume that the interface is initialy flat ( <math>  \hat h_q(0) =0 </math>), and note that <math> E_{pot} (t) = ( L \sigma/2) \sum_q q^2 h_q(t)h_{-q}(t)  </math>
* Compute
<center> <math> \Epsilon (t) =( L \sigma/2)  q^2 \langle h_q(t)h_{-q}(t) \rangle  </math> </center>
which describes how the noise injects the energy on the different modes. Comment about  equipartition and the dynamics exponent 
* Compute the width
<center> <math> \langle h(x,t)^2\rangle = \sum_ \langle h_q(t)h_{-q}(t) \rangle  </math> </center>
Comment about the roughness of the interface and the growth at short times.
* Compute the width

Revision as of 18:06, 27 December 2023

Goal: The physical properties of many materials are controlled by the interfaces embedded in it. This is the case of the dislocations in a crystal, the domain walls in a ferromagnet or the vortices in a supercoductors. In the next lecture we will discuss how impurities affect the behviour of these interfaces. Today we focus on thermal fluctuations and introduce two important equations for the interface dynamics: the Edward Wilkinson euqation and the Kardar Parisi Zhang equation.

An interface at Equilibrium: the Edward Wilkinson equation

Consider domain wall h(r,t) fluctuating at equilibrium at the temparature T. Here t is time, r defines the d-dimensional coordinate of the interface and h is the scalar height field. Hence, the domain wall separating two phases in a film has d=1,r, in a solid instead d=2,r𝟐.

Two assumptions are done:

  • Overhangs, pinch-off are neglected, so that h(r,t) is a scalar univalued function.
  • The dynamics is overdamped, so that we can neglect the inertial term.

Derivation

The Langevin equation of motion is

th(r,t)=μδEpotδh(r,t)+η(r,t)

The first term δEpot/δh(r,t) is the elastic force trying to smooth the interface, the mobility μ is inversily proportional to the viscosity. The second term is the Langevin Gaussian noise defined by the correlations

η(r,t)=0,η(r,t)η(r,t)=2Dδd(rr)δ(tt)

The symbol indicates the average over the thermal noise. The diffusion constant is fixed by the Eistein relation (fluctuation-dissipation theorem):

D=μKBT

The potential energy of surface tension can be expanded at the lowest order in the gradient:

Epot=σddr1+(h)2const.+σ2ddr(h)2

Setting μ=1,σ=1/2 we have the Edward Wilkinson equation:

th(r,t)=2h(r,t)+η(r,t)

Scaling Invariance

The equation enjoys of a continuous symmetry because h(r,t) and h(r,t)+c cannot be distinguished. This is a conndition os scale invariance:

h(br,bzt)inlawbαh(r,t)

Here z,α are the dynamic and the roughness exponent rispectively. From dimensional analysis

bαzth(r,t)=bα22h(r,t)+bd/2z/2η(r,t)

From which you get z=2 in any dimension and a rough interface below d=2 with α=(2d)/2.

Exercise L2-A: Solve Edward-Wilkinson

For simplicity, consider a 1-dimensional line of size L with periodic boundary conditions. It is useful to introduce the Fourier modes:

h^q(t)=1L0Leiqrh(r,t),h(r,t)=qeiqrh^q(t)

Here q=2πn/L,n=,1,0,1, and recall 0Ldreiqr=Lδq,0.

  • Show that the EW equation writes
th^q(t)=μσq2h^q(t)+ηq(t),withηq1(t)ηq2(t)=DLδq1,q2δ(tt)

The solution of this first order linear equation writes

h^q(t)=h^q(0)+0tdseμσq2sηq(s)

Assume that the interface is initialy flat ( h^q(0)=0), and note that Epot(t)=(Lσ/2)qq2hq(t)hq(t)

  • Compute
E(t)=(Lσ/2)q2hq(t)hq(t)

which describes how the noise injects the energy on the different modes. Comment about equipartition and the dynamics exponent

  • Compute the width
h(x,t)2=hq(t)hq(t)

Comment about the roughness of the interface and the growth at short times.

  • Compute the width