TBan-I

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In the following exercises, we will use the notation from extreme value statistics as introduced in the course.

Exercise 1: The Gumbel Distribution

In the spirit of the central limit theorem, you look for a scaling form:

Emin=aM+bMz


The constants aM and bM absorb the dependence on M, while the random variable z is distributed according to a probability distribution that does not depend on M.

In the Gaussian case, expand A(E) around aM:

By setting

aM=Emintyp=−σ2log⁡M+…andbM=1A′(aM)=σ2log⁡M

you find


exp⁡(A(aM))=1MandQM(E)≡Prob(Emin>E)∼exp⁡[−exp⁡(E−aMbM)]


Therefore, the variable z=(E−aM)/bM is distributed according to an M-independent distribution.

It is possible to generalize this result and classify the scaling forms into the Gumbel universality class:

  • Characteristics:
    • Applies when the tails of p(E) decay faster than any power law.
    • Examples: the Gaussian case discussed here or exponential distributions p(E)=exp⁡(E)withE∈(−∞,0).
  • Scaling Form:
P(z)=exp⁡(z)exp⁡(−ez)

esercizio 2: The weakest link

Exercise 3: number of states above the minimum

Definition of n(x):Given a realization of the random energies E1,E2,…,EM, define

n(x)=#{i∣Emin<Ei<Emin+x}

that is, the number of random variables lying above the minimum

Emin

but less than

Emin+x

. This is itself a random variable. We are interested in its mean value:

n(x)‾=∑k=0M−1kProb[n(x)=k]

The Final goal is to show that, for large M (when the extremes are described by the Gumbel distribution), you have:

n(x)‾=ex/bM−1

Step 1: Exact manipulations: You start from the exact expression for the probability of k states in the interval:

Prob[n(x)=k]=M(M−1k)∫−∞∞dEp(E)[P(E+x)−P(E)]k[1−P(E+x)]M−k−1

To compute n(x)‾, you must sum over k. Use the identity

∑k=0M−1k(M−1k)(A−B)kBM−1−k=(A−B)ddA∑k=0M−1(M−1k)(A−B)kBM−1−k=(M−1)(A−B)AM−2

to arrive at the form:

n(x)‾=M(M−1)∫−∞∞dEp(E)[P(E+x)−P(E)](1−P(E))M−2=M∫−∞∞dE[P(E+x)−P(E)]dQM−1(E)dE

where QM−1(E)=[1−P(E)]M−1.

Step 2: the Gumbel limit So far, no approximations have been made. To proceed, we use QM−1(E)≈QM(E) and its asymptotics Gumbel form:

dQM−1(E)dEdE∼exp⁡(E−aMbM)exp⁡[−exp⁡(E−aMbM)]dEbM=eze−ezdz

where z=(E−aM)/bM.

The main contribution to the integral comes from the region near E≈aM, where P(E)≈e(E−aM)/bM/M.


Compute the integral and verify that you obtain:

n(x)‾=(ex/bM−1)∫−∞∞dze2z−ez=ex/bM−1