LBan-II

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Introduction: Interfaces and Directed Polymers

The physical properties of many materials are governed by manifolds embedded in them. Examples include: dislocations in crystals, domain walls in ferromagnets or vortex lines in superconductors. We fix the following notation: - D: spatial dimension of the embedding medium – d: internal dimension of the manifold – N: dimension of the displacement (or height) field

These satisfy the relation:

D=d+N

We focus on two important cases:

Directed Polymers (d = 1)

The configuration is described by a vector function: x(t), where t is the internal coordinate. The polymer lives in D=1+N dimensions.

Examples: vortex lines, DNA strands, fronts.

Although polymers may form loops, we restrict to directed polymers, i.e., configurations without overhangs or backward turns.

Interfaces (N = 1)

The interface is described by a scalar height field: h(r,t), where rd is the internal coordinate and t represents time.

Examples: domain walls and propagating fronts

Again we neglect overhangs or pinch-off: h(r,t) is single-valued

Note that using our notation the 1D front is both an interface and a directed polymer

Directed polymers in random media

We now reanalyze the previous problem in the presence of quenched disorder. Instead of discussing the case of interfaces, we will focus on directed polymers. Let us consider polymers x(τ) of length t. The energy associated with a given polymer configuration can be written as

E[x(τ)]=0tdτ[12(dxdτ)2+V(x(τ),τ)]

The first term describes the elastic energy of the polymer, while the second one is the disordered potential, which we assume to be

V(x,τ)=0,V(x,τ)V(x,τ)=Dδ(xx)δ(ττ).

where 'D' is the disorder strength.


Polymer partition function and propagator of a quantum particle

Let us consider polymers starting in 0, ending in x and at thermal equilibrium at temperature T. The partition function of the model writes as

Z(x,t)=x(0)=0x(t)=x𝒟x(τ)exp[1T0tdτ12(τx)2+V(x(τ),τ)]

Here, the partition function is written as a sum over all possible paths, corresponding to all possible polymer configurations that start at 0 and end at x, weighted by the appropriate Boltzmann factor.


Let's perform the following change of variables: τ=it. We also identifies T with and t~=it as the time.

Z(x,t~)=x(0)=0x(t~)=x𝒟x(t)exp[i0t~dt12(tx)2V(x(t),t)]

Note that S[x]=0t~dt12(tx)2V(x(t),t) is the classical action of a particle with kinetic energy 12(τx)2 and time dependent potential V(x(τ),τ), evolving from time zero to time t~. From the Feymann path integral formulation, Z[x,t~] is the propagator of the quantum particle.


Feynman-Kac formula

Let's derive the Feyman Kac formula for Z(x,t) in the general case:

  • First, focus on free paths and introduce the following probability
P[A,x,t]=x(0)=0x(t)=x𝒟x(τ)exp[1T0tdτ12(τx)2]δ(0tdτV(x(τ),τ)A)
  • Second, the moments generating function
Zp(x,t)=dAepAP[A,x,t]=x(0)=0x(t)=x𝒟x(τ)e1T0tdτ12(τx)2p0tdτV(x(τ),τ)
  • Third, consider free paths evolving up to t+dt and reaching x :
Zp(x,t+dt)=ep0t+dtdτV(x(τ),τ)=ep0tdτV(x(τ),τ)epV(x,t)dt=[1pV(x,t)dt+]Zp(xΔx,t)Δx

Here is the average over all free paths, while Δx is the average over the last jump, namely Δx=0 and Δx2=Tdt.

  • At the lowest order we have
Zp(x,t+dt)=Zp(x,t)+dt[T2x2ZppV(x,t)Zp]+O(dt2)

Replacing p=1/T we obtain the partition function is the solution of the Schrodinger-like equation:

tZ(x,t)=H^Z=[T2d2dx2+V(x,τ)T]Z(x,t)

Z[x,t=0]=δ(x)

Remarks

Remark 1:

This equation is a diffusive equation with multiplicative noise V(x,τ)/T . Edwards Wilkinson is instead a diffusive equation with additive noise.

Remark 2: This hamiltonian is time dependent because of the multiplicative noise V(x,τ)/T. For a time independent hamiltonian, we can use the spectrum of the operator. In general we will have to parts:

  • A discrete set of eigenvalues En with the eigenstates ψn(x)
  • A continuum part where the states ψE(x) have energy E. We define the density of states ρ(E), such that the number of states with energy in (E,E+dE) is ρ(E)dE.

In this case Z[x,t] can be written has the sum of two contributions:

Z[x,t]=(eH^t)0x=nψn(0)ψn*(x)eEnt+0dEρ(E)ψE(0)ψE*(x)eEt.

In absence of disorder, one can find the propagator of the free particle, that, in the original variables, writes:

Zfree(x,t)=ex2/(2Tt)2πTt